X && Y, ||

X && Y

• if X is false, it doesn't matter what Y is

• x > 2 && y > 3 -> if the first condition is false, the second will not get evaluated

• this is because the entire expression will evaluate to false

• Implication: put the cheaper condition first, so there is a possibility to skip the evaluation of the second

X || Y

• only one condition needs to be true

• put the cheaper condition to evaluate first